Integration question: http://d.pr/RTc6
How do you solve it?
how do i integrate: \[π \int\limits_{0}^{6} (y ^{2}/12 +1)^{2} dy\]
Rotate the rectangle first, then rotate the parabola itself, find individual volumes then subtract the volume of the solid generated by the parabola from the solid generated by the rectangle
and for that integral, just multiply it out.
And then integrate term by term that will make your life easy.
actually finding the vol of the solid generated by the rectangle is easy.
I've been taught to integrate like this when the limits are on the y axis: \[\int\limits_{a}^{b} π x ^{2} dy\]
It generates a cylinder with radius 6 and height 4
Yea but you don't really have to do that for the solid generated by the rectangle. If you rotate it around it generates a cylinder.
What rectangle are you referring to?
Imagine a line passing through (4,6) and (4,0)
that will form a rectangle right? with the line y = 6, x = 4, and x and y axes
yes, i see. But what do you after that?
you can do this with disk or shell method. Do you know both?|dw:1329324049040:dw|
So find the volume of the solid generated by that rectangle - it will be a cylinder
I haven't heard of the 'disk' or 'shell' method?
What do i do after working out the vol. of solid rectangle?
Find the volume generated by revolving the following area and then subtract it from the vol of the cylinder.
|dw:1328460177913:dw|
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