Question

A group of 8 boys and 6 girls are to stand in a straight line for a photograph. In how many ways can these 14 children be arranged so that none of the girls stand next to each other?

Answer 1

\( \large ^9P_6 \times 8! = \cdots \)

Answer 2

@FoolForMath how did you get that?

Answer 3

There are 9 places for 6 girls to go so that no girls would be together.

Answer 4

2438553600

Answer 5

but there are only 7 places available so that the girls are not together

Answer 6

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Answer 7

two boys could be together too and yet the girls will be separated...

Answer 8

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