Question

can someone check and see if this is right?

Answer 1

\[\int\limits_{?}^{?}(1+4x)/(\sqrt{1+x+2x ^{2}}dx\]

Answer 2

i got
\[.5\ln \left| \sqrt{1+x+2x ^{2}} \right| +c\]

Answer 3

\[u = 1 + x + 2x^2, du = (1 + 4x) dx\]

Answer 4

it looks wrong

Answer 5

There is no log. Instead it is \[2 \sqrt{ 1 + x +2x^2}\]

Answer 6

why could you not use ln

Answer 7

well, the integral becomes \[\int\limits_{}^{} \frac {du}{u^.5}\]

Answer 8

\[\int\limits_{}^{} = u^{-.5}du\]

Answer 9

\[\int\limits \frac{f'(x)}{f(x)}dx=lnf(x)\]

Answer 10

oops. There isn't supposed to be an equal sign in the integral.

Answer 11

ok i think i got it

Answer 12

Alright, just the use power rule for integration to solve.

Answer 13

thanks