What does it mean if a set is "closed with respect to addition?" What about multiplication?
It means that whenever you add any two members of the set your answer is also a member os the set.
of the set. I meant
Example please?
I'll give you sets and will you tell me if they are? {1,2}-I think no because there is no 3 {1,2,3}- think yes because 1+2=3 {1,2,3,4}-would it be because 1+2 = 3, or would it not be because 1+4 = 5
If it's the same way for multiplication, does that mean any set with a one and something else in it is closed to multiplication?
the set of all positive numbers is closed under addition: whenever you add positive numbers you get another positive number as an answer {1,2} is not closed under addition because 1+2=3 and 3 is not a member of the set {1,2}. it is closed under multiplication though, because 1*2=2 which is an element of the set
(the set of positive real numbers is also closed under multiplication too)
so it just has to have at least one number in it that is the sum or product of two other numbers in it?
no, {1,2,3} is closed under neither addition nor multiplication, because 3+1=4 (not a member) and 2*3=6 (not a member) so as long as there is any way to produce a member outside the set, that set is not closed under that operation.
...no matter that 1+2=3, there exists a way to create an element outside the set, so it is not closed
are you sure? it seems like I heard differently. But I'm unsure so I'll go with you.
My understanding is as I said it, and quoting mertsj: "It means that whenever you add any two members of the set your answer is also a member os the set." seems like that's the same thing here's something from online: http://mathforum.org/library/drmath/view/52452.html
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