Question

2-3i/1-2i

Answer 1

conjugate

Answer 2

\[\frac{2-3i}{1-2i}\times \frac{1+2i}{1+2i}\]
\[\frac{(2-3i)(1+2i)}{1^2+2^2}\]
then multiply in the numerator

Answer 3

(2-3i/1-2i)*(1+2i/1+2i)

Answer 4

\[\frac{8+i}{5}=\frac{8}{5}+\frac{1}{5}i\]

Answer 5

got that far then once I multiplied it out I'm coming up with 2+9i/1+4i when the book says 8/5+1/5i

Answer 6

how did you get the 8

Answer 7

I am coming up with 2+7i/1+4i where did the 8 come from?