Question

calculus: example
indeterminate form
lim (f(x) - f(2))/x-2 if f(x) = x^2 - 3x if x approaches 2.

Answer 1

the prof answer is 1 but i want to learn where did he get solution ((x-2) (x-1)/(x-2)
the (x-1)

Answer 2

f(2)=4-6=-2
so f(x)-f(2)=x^2-3x+2=(x-2)(x-1).....
when you divide it with (x-2) you get x-1
so lim of (x-1) as x approaches to 2 is 1

Answer 3

ahhhh ic ic so if x approaches to 3 = 2? now i know

Answer 4

= (x^2-3x - [(2)^2 - 3(2)])/x-2
=lim x approaches 2 (x^2 - 3x - (-2)/x-2
=lim x approaches 2 (x^2 - 3x +2)/x-2
= (4-3(2)+2)/2-2
= 0/0
=lim x approaches 2 ((x-2)(x-1))/(x-2)
=lim x approaches 2 (x-1)
= 2-1 = 1 answer solution of my prof ^^

Answer 5

yes i learn again yes im slow but i learn again yes!