IF X=18 (+ or -) 0.5 and Y= 9.0 (+ or -) 0.4, find appropriate values, including errors, for: X+Y X-Y X+2Y 2X-3Y X * Y X / Y sqr(XY XY^3
hold on
If we wanted to include the endpoints we would write [2,4]. If we wanted to ...... \frac{1}{xy^5}. 35. \sqrt{x^2y^4}. xy2. 36. \bigg(\frac{8x^6}{y^4}\. \frac{2x^2}{y^{4/3}}
2.5 Mean Square Approximation and Parseval's Identity 16 .... ((x + 3)( U−3 − U−2) + (2x + 5)( U−2 − U−1) + (x + 4)( U−1 − U0) ... 18 x cos 3x + ∑. 6 n=1, n=3 sin nx n(9−n2) . # 49: yp = ... ↔ yp = x(.... # 67: y = − .... Same reasoning as in the previous exercise, we find the solution ...... So u(xy) = T if and only if 2xy = T if and only
do u get it?
this doesnt make any sense, are you sure your doing it the right way
yep
here let me put it another way
all we have to do is add X +Y for the first one 18 + 9.0 = 27 then do you just add the uncertainties? .5+.4= .9 27 + or - .9 ???
If we wanted to include the endpoints we would write [2,4]. 2.5 Mean Square Approximation and Parseval's Identity 16 .... ((x + 3)( U−3 − U−2) + (2x + 5)( U−2 − U−1) + (x + 4)( U−1 − U0) ... 18 x cos 3x + ∑. 6 n=1, n=3 sin nx n(9−n2) .
Same reasoning as in the previous exercise, we find the solution ...... So u(xy) = T if and only if 2xy = T if and only
No this is none of that, this is physics lol
is my answer correct?
Of course. yes yes yes
ok so you add the uncertainties?
yep
x+2Y = 36 + or - 0.9??
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