Question

I'm lost,
Estimate the area of the shaded region in the graph by using the Trapezoidal Rule with n=4.

Answer 1

trap rule eh ...

Answer 2

Yeah, that one...

Answer 3

the area of a trap is average of the height * width

f(1)+f(2)
------- * 1 if the width is 1 that is
2

Answer 4

do it for each section

Answer 5

\[\frac{f(0)+f(1)}{2}*\frac{b-a}{4}+\frac{f(1)+f(2)}{2}*\frac{b-a}{4}+\frac{f(2)+f(3)}{4}*\frac{b-a}{4}+\frac{f(3)+f(4)}{4}*\frac{b-a}{4}\]
\[\frac{b-a}{2*4}(f(0)+f(1)+f(1)+f(2)+f(2)+f(3)+f(3)+f(4))\]
\[\frac{b-a}{2*4}(f(0)+2f(1)+2f(2)+2f(3)+f(4))\]

Answer 6

But how? They don't even label the graph,

Answer 7

0, 6, 9.5 .. just count and estimate the best you can with the intersections

Answer 8

0, 6, 9.5 ,4, 2

0 + 12 + 19 + 8 + 2

41/8 = 5*(b-a)

Answer 9

b-a looks to be 16

Answer 10

41/8 * 16 = 41*2 = 82 or so? does that fit an answer?

Answer 11

Possible choices are:

12
10.5
6.9
8.5
7.4
12.5

Answer 12

Kinda accurate for an estimate

Answer 13

i counted each little blip as 4 so im a little off

Answer 14

each blip might be 1/4

Answer 15

0+2*1.5+2*2.5+2*1+.5

3+5+2+.5 = 10.5
4
-----
42.0/(2*4)

42/8 = 5.somehting as far as I can tell

Answer 16

Which still isn't close to any of their answers, hmm

Answer 17

whered you get this program at; biglots?

Answer 18

what?

Answer 19

biglots is a store that has a rep of subpar merchandise :)

Answer 20

Yeah, lol I know that, I was wondering what you meant by "program"

Answer 21

:) i assumed you were working this from a program

Answer 22

Ah, no I was trying to do it by good ole' paper :P

Answer 23

well, the concept I believe is sound:

b-a/n = width

and the average of yor heights is the height

b*h = area for each section

Answer 24

I found one similar online where I believe they got 11.5,

http://www.csuchico.edu/~rford/MATH7BWEB/Math7BQuizzes/Math%207B%20Exam%202%20Review

Answer 25

do we have numbers to go with yours?

Answer 26

nope...

Answer 27

then all we can do is assume a basic interval if 1 per "tic" that i know of

Answer 28

but then one box is over 16

Answer 29

4 per box would be 4 tics wide

Answer 30

0 to 6 has an avg of 3

6 to 10 has an avg of 8

10 to 4 has an avg of 7

4 to 2 has an avg of 3

4(3+3+8+7)

4(21) = 84 total

Answer 31

other than that, its just a guessing game to figure our what it is they are scaling hteir tic marks as

Answer 32

hmm, I do believe that I got points taken off in Physics for not labeling my graphs like that, lol

Answer 33

i need help on http://openstudy.com/study#/updates/4f3084efe4b0fc09381eed4a asap pretty please!!!!

Answer 34

Hey, I called him first :P