let f(x)= 2/1+x^2. The equation of the tangent line to the curve at the point (5,0.07692) can be written in the form y=mx+b where m is: ?
and b is?

Question

let f(x)= 2/1+x^2. The equation of the tangent line to the curve at the point (5,0.07692) can be written in the form y=mx+b where m is: ?
and b is?

anonymous · Answer

m = 2x at x=5

anonymous · Answer

y-y1=m(x-x1)

anonymous · Answer

y1 x1 are your points plug, rearrange, and determine your values

turingtest · Answer

point-slope form for algebra is this:$$y-y_1=m(x-x_1)$$now in calculus we learn that slope of the tangent at a point 'a' is the derivative at that point$$m=f'(a)$$so we need the coordinates of the point$$(x_1,y_1)$$and the value of the derivative $$f'(x_1)$$then we can use the modified point-slope form$$y-y_1=f'(x_1)(x-x_1)$$

turingtest · Answer

rearrange into slope intercept form...