A cylindrical rod has a length of 73 cm and a diameter of 1.2 mm. What is the cross-sectional area in m^2?

Question

A cylindrical rod has a length of 73 cm and a diameter of 1.2 mm.  What is the cross-sectional area in m^2?

anonymous · Answer

pi*(d/2)^2
convert d to m
1.2 mm = 0.0012 m

I think that's what they're asking

anonymous · Answer

note that d/2 is actually just r, the radius
and pi*r^2 is the area of a circle

anonymous · Answer

i thought the answer was 1.13e-6?

anonymous · Answer

well how did you get that?

anonymous · Answer

.12 x pi / 4

anonymous · Answer

were you able to verify that somehow, because to me that looks incorrect

anonymous · Answer

no

anonymous · Answer

http://answers.yahoo.com/question/index?qid=20100204064536AAIBPm2

anonymous · Answer

oh yep that is correct, sorry. my blank was forgetting to divide the diameter by 2 in my calculation. even though i stated what to do properly above aha.

anonymous · Answer

a = pi(0.0012/2)^2
that is the formula I would use. So long as it makes sense to you