Question

consider the following quadratic function...k(x)=(x-6)..find the vertex of this function

Answer 1

that's not a quadratic function

Answer 2

is (x-6) raised to the 2nd power?

Answer 3

no...it's not on the problem...that's how it's worded

Answer 4

k(x)=x-6 is a line

Answer 5

I have the answer..I just don't understand how to do the problem...the answer is (6,0)

Answer 6

Well, I'm going to assume it is k(x)=(x-6)^2
Expand: x^2-12x+36
The vertex of a parabola written in the for ax^2+bx+c is:
\[(-\frac{b}{2a},f(-\frac{b}{2a})\]
\[(\frac{12}{2},f(\frac{12}{2}))=(6,f(6))=(6,0)\]

Answer 7

looks good....worked it out..now quick question...why is f(6)=0?

Answer 8

f(6)=6^2-12(6)+36=36-72+36=0

Answer 9

or in the original form,
f(x)=(x-6)^2
f(6)=(6-6)^2=0^2=0

Answer 10

makes sense now thank you