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plzz help me now....... if cosy=xcos(a+y) theprove that dy/dx=(cos^2 (a+y))/sina
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i jst dbtknw ...y i g8 stuck wit simple sums....:(
using implicit differentiation: \[\frac{dy}{dx} = \frac{\cos(a+y)}{x \sin(a+y)-\sin(y)}\]
then im guessing use sum of angles formula
sin(a+y) = sin(a)cos(y) + sin(y)cos(a)
\[shouldnt ittt be -\sin(y) dy/dx =-\sin(a+y)x+coas(a+y)\]
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i don't know if im helping :| there should be a dy/dx with the -sin(a+y)x term
ywesssss it shud b sry it din write
pellet....yes u r write....mdumb :P
*pellettt
*pelletttt
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***crap...
censorship even here??? :P
haha from here though im not sure where to go, they don;t have an x in their answer ...i don't see how the x cancels anywhere
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