Question

need to find m so that y=mx+5 has a common intersection point with y=7x+43 and y=8x+53

Answer 1

Do you mean same common intersection point

Answer 2

If no all values of m except 7,8

Answer 3

i need to find a value for the slope for thee first equation so it has a common intersection point with the other 2

Answer 4

m=16/5

Answer 5

unfortunately that didn't solve it

Answer 6

Do you know how to find the intersection point of the two given lines?

Answer 7

I mean y=7x+43 and y=8x+53.

Answer 8

The two lines intersect \(7x+43=8x+53 \implies x=-10\).
Substitute \(x=-10\) in either equation you get \(y=-70+43=-27\). So the intersection point is \(-10,-27\). Plug this point in the first equation and solve for m.

Answer 9

Mr Math says the same

Answer 10

I did it using determinats

Answer 11

Yes, NotSObright is so bright and he's right.

Answer 12

You basically have to solve:
\[-27=-10m+5 \implies m=\frac{32}{10}=\frac{16}{5}.\]

Answer 13

my mistake. Thank you to both of you. The online program I use is picky... did not have to simplify to 16/5. successful using 32/10