need to find m so that y=mx+5 has a common intersection point with y=7x+43 and y=8x+53

Question

anonymous · Answer

Do you mean same common intersection point

anonymous · Answer

If no all values of m except 7,8

anonymous · Answer

i need to find a value for the slope for thee first equation so it has a common intersection point with the other 2

anonymous · Answer

m=16/5

anonymous · Answer

unfortunately that didn't solve it

mr.math · Answer

Do you know how to find the intersection point of the two given lines?

mr.math · Answer

I mean y=7x+43 and y=8x+53.

mr.math · Answer

The two lines intersect $7x+43=8x+53 \implies x=-10$.
Substitute $x=-10$ in either equation you get $y=-70+43=-27$. So the intersection point is $-10,-27$. Plug this point in the first equation and solve for m.

anonymous · Answer

Mr Math says the same

anonymous · Answer

I did it using determinats

mr.math · Answer

Yes, NotSObright is so bright and he's right.

mr.math · Answer

You basically have to solve:
$$-27=-10m+5 \implies m=\frac{32}{10}=\frac{16}{5}.$$

anonymous · Answer

my mistake.  Thank you to both of you.  The online program I use is picky... did not have to simplify to 16/5.  successful using 32/10