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OpenStudy (anonymous):
(2/3)^abslx+2l=(81/16)^-3
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OpenStudy (anonymous):
\[(\frac{81}{16})^{-3}=(\frac{16}{81})^3=(\frac{2^4}{3^4})^3\] \[=(\frac{2}{3})^{12}\]
OpenStudy (anonymous):
this tells you \[|x+2|=12\] so \[x=2=12\] or \[x+2=-12\]
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