A baseball player hits a homerun, and the ball lands in the left field seats, which is 120 m away from the point at which the ball was hit. The ball lands with a velocity of 20 m/s at an angle of 30 degrees below horizontal. Ignoring air resistance (A) find the initial velocity and the angle above horizontal with which the ball leaves the bat; (B) find the height of the ball relatively to the ground
If there is no air resistance, the parabolic path will be symmetrical, and thus it will land at the same velocity with which it left. So \[u=20 m/s and \theta=30\] The height will be \[h=u ^{2}\sin ^{2}\theta/2g\]
it is like that concept in which when u fire a bullet vertically up,it comes down same straight line to hit u with same speed with which it went if not for air drag
there is a common principle that when a body is thrown up from a certain height,then when it comes back to the same height, it will have the same velocity
|dw:1328876734968:dw||dw:1328876550335:dw| sincew the magnitude of velocity is same however when u see the angle made with the horizontal,first it is theta and next it is 189-theta
Join our real-time social learning platform and learn together with your friends!