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How many liters of water vapor can be made from the reaction of 23.8 grams of H2 with excess O2 at standard temperature and pressure? 2 H2 (g) + O2 (g) → 2 H2O (g)
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moles of hydrogen=mass/mw as from stoichiometery coefficeint moles of hydrogen will be equal to moles of water vapour so just find the mole :))
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