Question

At what POINTS is this function continuous..y=cosx/x...someone please explain to me how to solve these types of problems? is it whatever numbers make this an undefined problem?

Answer 1

well x=/=0

Answer 2

i would say limit x>0 \[(-\infty,0)\]\[(0,\infty)\]

Answer 3

but im a nub so dont trust me much

Answer 4

the book says all x except x=0 so yes ur on it, but like, do u just see this problem n knw, or do u go thru a guess n check process, what process do u go thru to get an answer for these types of problems?

Answer 5

well the denominator can never be 0

Answer 6

so x cannot be 0

Answer 7

not much to guess at really

Answer 8

just means if x were zero

Answer 9

the value would be undefined

Answer 10

hence a hole in your graph

Answer 11

got it! ok i got one more...

Answer 12

y=sqrt(2x+3)

Answer 13

well since it is a square root is can never be negative

Answer 14

so it would be \[(0,\infty)\]

Answer 15

the graph of a square root function looks like

Answer 16

the books answer is, all X greater than or equal to -3/2

Answer 17

yea thats right

Answer 18

because

Answer 19

y=sqrt(2x+3)

Answer 20

to make the square root 0 x would have to be -3/2

Answer 21

hence its still not a negative

Answer 22

been up all night sorry

Answer 23

getting tired

Answer 24

but since -3/2 make it the sqrt of 0 thats the limit

Answer 25

all other numbers have toi be greater then -3/2

Answer 26

so if u plug in -3/2 "sqrt(2(-3/2)+3" this will equal 0?

Answer 27

yes because the 2's cancel

Answer 28

2x-3/2 = -3

Answer 29

-3+3 = 0

Answer 30

got it! so on these types of problems are u really just looking for w/e numbers will make it undefined?

Answer 31

basically

Answer 32

and if you cannot make it undefined

Answer 33

its continuous from -inf to +inf

Answer 34

ok well you have a good one, gotta get some rest now

Answer 35

thanks!