f(x,y) is notcontinous at the origin? if not why?
1.f(x,y) is continous at origin
2.f(0,0) is not defined.
3.f(0,0) is defined but limit of f(x,y) does not exist.
4.f(0,0) is defined and limit exits but therse two number are not equal?

Question

f(x,y) is notcontinous at the origin? if not why?
1.f(x,y) is continous at origin
2.f(0,0) is not defined.
3.f(0,0) is defined but limit of f(x,y) does not exist.
4.f(0,0) is defined and limit exits but therse two number are not equal?

anonymous · Answer

where's the rest of the question?

anonymous · Answer

f(x,y) is 4xy+sin3x^2y

anonymous · Answer

3?

anonymous · Answer

how do u know this ? can you please give me hint ???

anonymous · Answer

is that the right answer?

anonymous · Answer

i think it is 1, lim x-> 0 sinx does exist, so 3 does not work, and i dont quite know what 4 means but i dont think it is correct, and it is defined i think so it must be 1.

anonymous · Answer

but 0^0 is 1 is not? in calculus?

anonymous · Answer

and sin of 1 is not 0

anonymous · Answer

or sin of 3*

anonymous · Answer

0^0 is not defined

anonymous · Answer

yeah you're right.

anonymous · Answer

woops i didnt notice the exponential sign, for some reason thought it was 0*0 not 0^0. but for these purposes i think it can be defined as 1 anyways

anonymous · Answer

no funinabox i was wrong about that. 0^0 is undefined.

anonymous · Answer

depends on your definition of 0^0 i suppose

anonymous · Answer

|dw:1328954020126:dw|how is it one? when limit x tends to 0