If any tangent to the ellipse \frac{X^2}{a^2} + \frac{Y^2}{b^2}=1 \) intercepts equal length \(L\) on the axes then find \( L\) Sadly it took me more than 5 mints to solve this, how much do you take? ... Am I having intellectual atrophy?
If any tangent to the ellipse \( \frac{X^2}{a^2} + \frac{Y^2}{b^2}=1 \) intercepts equal length on the axes then find L Sadly it took me more than 5 mints to solve this, how much do you take? ... Am I having intellectual atrophy?
Thanks for the medal zed, do you think it's a good problem? or am I just becoming slow? :(
I thought it was a good problem, but it is 1am here. xP
haha, well I am out practice so it seemed soo hard :D
saso, give it a shot!
seriously?
that's beyond me lol
lol, comeon it's not that hard, just High school stuffs :)
well at the moment, I know zero about ellipses or formulas related to them so that's like entering a new town and someone asks you for direction..
at the moment i have exams through out the next 2 weeks so no studying, just revision, after the exam when i start studying, i may come across ellipses and i may be able to solve it :) but if anyone does solve it, i'll take a look at the solution, will get a fair idea what the whole thing is about and when i get to study it, shouldn't be difficult :)
That's the spirit saso!
If I understand this correctly, the slope of the tangent must be 1 or -1 - is that right?
|dw:1328995207131:dw| is this an example of what the question is asking?
assuming my interpretation of the question is correct, I think the answer is:\[L=\frac{a^2\pm b^2}{\sqrt{a^2+b^2}}\]
there are 4 possible tangents here
yes - I drew one example
if i understand x and y to be the points where the tangents cut the axes, then what's a and b?
|dw:1328995752214:dw|
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