Question

find the unit and normal vectors:

r(t) =

Answer 1

unit tangent and normal?

Answer 2

r(t) = <T,1/2(T^2), T^2>

r'(t) = <1,T, 2T>

r''(t) = <0,1,2>

divide each one by its magnitiude to unit it out

Answer 3

5 feet divide by 5 gives 1 foot

16 inches divided by 16 gives 1 inch

150 yards divided by 150 gives 1 yard

Answer 4

okay so i got the tangent as 1/\[\sqrt{5T ^{2}+1}\], T/\[\sqrt{5T ^{2}+1}\], and 2T/\[\sqrt{5T ^{2}+1}\]

Answer 5

but then normal i have to do derivitive of that so it seems too complicated

Answer 6

i already did the derivative for the normal; r''=<0,1,2>; units to /sqrt(5)