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Sequences: Prove the sum from n=1 to infinity of 1/(n(n+1))=1...
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write as a telescoping sum
Hint: \( \large \frac{1}{n (1+n)} = \frac1n - \frac1{(n+1)} \)
The partial sum would be \[ 1-\frac{1}{1+n } \] now if you take the limit to infinity you will get your desired result.
\[\sum_{n=1}^{\infty} 1/(n(n+1)) =1\] Know that \[\sum_{k=1}^{\infty} 1/(k(k+1)) = \sum_{k=1}^{\infty} [1/k - 1/(k+1)]\] Okay - this is real analysis and I haven't had Calculus in about 6 years. So I just take lim (n-> infty) of the sum?
I'm slow typing...thanks for the help.
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Glad to help :)
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