Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Sequences: Prove the sum from n=1 to infinity of 1/(n(n+1))=1...

OpenStudy (zarkon):

write as a telescoping sum

OpenStudy (anonymous):

Hint: \( \large \frac{1}{n (1+n)} = \frac1n - \frac1{(n+1)} \)

OpenStudy (anonymous):

The partial sum would be \[ 1-\frac{1}{1+n } \] now if you take the limit to infinity you will get your desired result.

OpenStudy (anonymous):

\[\sum_{n=1}^{\infty} 1/(n(n+1)) =1\] Know that \[\sum_{k=1}^{\infty} 1/(k(k+1)) = \sum_{k=1}^{\infty} [1/k - 1/(k+1)]\] Okay - this is real analysis and I haven't had Calculus in about 6 years. So I just take lim (n-> infty) of the sum?

OpenStudy (anonymous):

I'm slow typing...thanks for the help.

OpenStudy (anonymous):

Glad to help :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Breathless: Spooky witch but cute
6 hours ago 3 Replies 0 Medals
Arriyanalol: help
6 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
9 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
9 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!