Question

how do you solve: f(x)= x^-4/x^-1

Answer 1

close. but I mean x squared minus 4/ x squared minus 1

Answer 2

Sorry
\[ \frac{x^{-4}}{x^{-1}}\]
tia what is \[\frac{1}{x^{-1}}\]?

Answer 3

x^-3

Answer 4

x^-4/x^-1
=
x^-3
f(x)=x^-3

Answer 5

understand?

Answer 6

I know the top is all real numbers so x can be any number. the bottom half I believe x can be any number except 1 since. 0 in the denominater is undefined.
in finding the domain of a function

Answer 7

don't understand

Answer 8

x^-4/x^-1
base -> x
potences -> -4 and -1
same bases, sub potences.
x^-4-(-1)
x^-4+1
x^-3
f(x)=x^-3

Answer 9

k

Answer 10

and now? understand?

Answer 11

yes

Answer 12

good. :) good study.