can i get some help with this question. We know that the quantity of tuna demanded and supplied is related to the price of tuna. Given that the demand function for tuna is q=(306.25-p)0.5+2.5 and the inverse supply function for tuna is p=76+3q. All quantities are in kilograms and prices in $TT. Determine the quantity of the tuna that will be demanded and supplies when the market is in equilibrium. NB 0.5 is to the power

Question

can i get some help with this question.  We know that the quantity of tuna demanded and supplied is related to the price of tuna. Given that the demand function for tuna is q=(306.25-p)0.5+2.5 and the inverse supply function for tuna is p=76+3q. All quantities are in kilograms and prices in $TT. Determine the quantity of the tuna that will be demanded and supplies when the market is in equilibrium. NB 0.5 is to the power

anonymous · Answer

is that parenthesis right in your question?

anonymous · Answer

q=(306.25-p)^0.5 + 2.5

anonymous · Answer

think of this that in equilibrium - supply is equal to demand.

anonymous · Answer

I know that much but how do I proceed

anonymous · Answer

is this calculus?  - I would subsitute p into the demand equation - note the .5 power is really a square root.  then set both q = p and solve for q

bimbim2697 · Answer

Junita can yhu help me plz?

anonymous · Answer

read my last post - what class is this for?

anonymous · Answer

This is a function question

anonymous · Answer

|dw:1329263038555:dw|oh got it - set q(x) = s(x).