a person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed the angle of depression to the boat is 19.45. when the boat stops, the angle of depression is 50.95. the light house is 200 ft tall. How far did the boat travel from when it was first noticed until it stopped?
Probably the most hated related rates problem
Isn't it just a case of 200tan(x)? Or am I missing something?
oh ur missing something
Go there, to get ideas on how to solve it
It doesn't have any rates or anything. It's just asking for distance...
dude hero i already looked at how to solve it and i did, i just want to know if it is right
lol
well then tell me what you get
|200tan(x_1)-200tan(x_2)| should give dr
and tell me what u get
im sure u missed something
Curry, you should probably try to find James J. He's the master
|dw:1329287201110:dw| d can be found by taking xtan(angle). No I'm not missing anything. >.>
Proof: tany=d/x-->xtany=d
change in d as angle y changes is |xtan(y_1)-xtan(y_2)|
|dw:1329287300450:dw| is think that is what it looks like
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