Mathematics
21 Online
OpenStudy (anonymous):
simplify (2/x^2+8x+15) + (1/x^2+11x+30)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
First step:
\[\frac{2}{(x+5)(x+3)}+\frac{1}{(x+6)(x+5)}\]
OpenStudy (anonymous):
Second step:
\[\frac{2(x+6)+(x+3)}{(x+5)(x+3)(x+6)}\]
OpenStudy (anonymous):
I'll let you take over
OpenStudy (anonymous):
can you cross out the x+3 and the x+6? and get 2/x+5
?
OpenStudy (anonymous):
no
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
You want to distribute the 2 to the numerator and rewrite the numerator
OpenStudy (anonymous):
so you would get 4x+18?
OpenStudy (anonymous):
\[\frac{2(x+6)+(x+3)}{(x+5)(x+3)(x+6)}=\frac{2x+12+x+3}{(x+6)(x+5)(x+3)}\]
\[=\frac{3x+15}{(x+6)(x+5)(x+3)}\]
Can you do the next step?
OpenStudy (anonymous):
so you dont distribute the 2 to x+3?
OpenStudy (anonymous):
No, there's a plus sign in between
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
oh gotcha
OpenStudy (anonymous):
You only distribute for multiplication
OpenStudy (anonymous):
There's only a little bit left to do
OpenStudy (anonymous):
combine
(x+5)(x+3)(x+6)?
OpenStudy (anonymous):
Nope, it has to do with the numerator first
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
can you factor anything out of the numerator?
OpenStudy (anonymous):
3
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
3(x+5)
OpenStudy (anonymous):
Right. Now you can cancel the (x-5) in the numerator with the one in the denominator
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
You're left with:
\[\frac{3}{(x+6)(x+3)}\]
OpenStudy (anonymous):
its an x+5 though is that okay?
OpenStudy (anonymous):
never mind they both are
OpenStudy (anonymous):
That's as far as it can be simplified. If you want to FOIL the denominator, that's up to you.
OpenStudy (anonymous):
thanks :)