Question

Help please. I need to know if I am right to this point and I need help with the rest.
Use the given information about a polynomial whose coefficients are real #s to find the remaining zeros of the polynomial.
Degree: 6
Zeros: 10+20i, -3-isqrt6, 19-20TTi
This is what I have; roots are 10+20i & 10-20i
(-3-isqrt6) ( -3 + isqrt6)
19-20TTi & 19+20TTi
polynomial is: ?

Answer 1

9 + 6 = 15
simple as that

Answer 2

x^2 - y^2 = (x+y)(x-y)
i^2 = -1
sqrt of 6 squared = 6
-3^2 = 9

Answer 3

so it's:
-3^2 - i^2(sqrt of 6)

Answer 4

Hint: try multiplying the roots in complex conjugate pairs. For example:

(x-(10+20I))*(x-(10-20I))