Question

Find the derivative of the function.
g(t) = e^(−9/t^(9))
g'(t) =

Answer 1

g'(t) = e^(−9/t^(9)) * (−9/t^(9))'

Answer 2

chain rule :)

Answer 3

chain rule :(

Answer 4

(−9/t^(9))' = (−9*t^(-9))'=81t^(-8)

Answer 5

what is the 81t^(-8)?

Answer 6

it's not g'(t), right?

Answer 7

zarkon, please help!

Answer 8

g(t) = e^(−9/t^(9))

\[g(t)=e^{\frac{-9}{t^9}}=e^{-9t^{-9}}\]

\[g'(t)=e^{-9t^{-9}}(-9)(-9)t^{-9-1}=e^{-9t^{-9}}81t^{-10}\]

Answer 9

ok?

Answer 10

where did the second (-9) come from?

Answer 11

\[\frac{d}{dt}\left(t^{-9}\right)=-9t^{-10}\]