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Mathematics 22 Online
OpenStudy (anonymous):

Find the x-coordinate of each point where the function has horizontal tangent line (2x^2-7)^3 I took the derivative but idk what to do after that its just a huge mess that idk how to factor

OpenStudy (accessdenied):

Well, first, what is true about a horizontal line and its slope/ rate of change?

OpenStudy (anonymous):

Posted this about 20 minutes ago, got a similar remark. I understand that you set the d to 0 my problem is the solving for x part.

OpenStudy (anonymous):

set d = 0*

OpenStudy (anonymous):

My section skipped over change of rate, were going back to it tomorrow. Does change of rate play a role in this problem?

OpenStudy (accessdenied):

Nope, I was just checking to be sure you knew up to that point... Well, do you remember the chain rule? We can see that the outside function is x^3 and the inner function is 2x^2 - 7 If we used the chain rule, we'd still have them in a 'factored' form where we have everything multiplied together.

OpenStudy (accessdenied):

I should probably say, are you familiar with it...

OpenStudy (anonymous):

Yeah I used the chain rule. got 12x( 4x^4 blah blah )^2

OpenStudy (anonymous):

dont have my work infront of my atm

OpenStudy (anonymous):

maybe i did it wrong.. lol

OpenStudy (anonymous):

i highly doubt that though

OpenStudy (accessdenied):

It looks like you may have simplified some stuff... What I get is " 3(2x^2 - 7)^2 (4x) "

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

got that but when I set that =0 im so lost as what to do

OpenStudy (accessdenied):

Have you ever done finding roots of quadratics with stuff like (x-3)(x+6) = 0 , setting each factor to zero? You'd pretty much do the same thing here with each factor: '3(4x)', '2x^2 - 7'. Those would be the x values that you are looking for. :)

OpenStudy (anonymous):

your kidding me so one of the answers is 0 and rad 7/2 are the answers?

OpenStudy (anonymous):

for the x cords

OpenStudy (accessdenied):

positive and negative rad(7/2). But yeah

OpenStudy (anonymous):

im an idiot..... thank you so much for some reason I didnt think you could use that. Thanks for your patience. You are probably the most helpful person I've encountered on OS

OpenStudy (accessdenied):

It is no problem. As long as you understand now! :) You'll probably use a lot of those things from algebra in calc. :P

OpenStudy (anonymous):

thats a good sign then! you sir or madam should be a math teacher!

OpenStudy (accessdenied):

I am male, in case you were wondering. I don't know, I'm still learning stuff myself yet.

OpenStudy (anonymous):

Learning calc? How far are you in math? LA, DEQ?

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