if g(x) = 2 tan(7x) what is g'(x)=
Really, hicks, this is not a place to be asking for answers. We help, we don't do homework.
thing is, i'm not doing this for a grade... i just don't understand how to begin these problems
(d/dx)f(g(x))=g'(x)f'(g(x)
this is the chain rule you need to take the derivative of the outside multiplied by the derivative of the inside. so first you need the derivative of tan(x)
the formula makes sense now, but i still don't know how to go about approaching all the different circumstances
like a sqrt, or exponent or log
i definately need some algebra review. i haven't taken a single math class in 8 years and my school is forcing me to take calculus without allowing me to take the pre-requisites. and i'm trying to graduate this year, so no options but desperately trying to pass and i'm WAAY in over my head
and none of my teachers or TAs speak english, so when i go to tutoring, we don't understand eachother
you just have to practice and you can see it. you will have either simple constants to powers, products(two functions multiplied or a function in a function. so first is to identify what is the form of the equation such as sin(2x) is a function in the sin function
there are other possibilities of functions other than powers, products or chains, but these are the most common
hicksonm, if you really want to learn, go to KhanAcademy. It's a deliberately paced learning environment that can fill in gaps of knowledge very well.
i've been practicing for hours, but i have to look up EVERY step EVERY time i get to it. i don't remember how to do anything... i don't remember how to simplify things
how much does it cost?
Davidjohn, thanks for the explaination. that makes more sense than the variable soup in my book
oh my gosh, KhanAcademy is free! i'm watching one of their algebra videos now!
thank you thank you! finally, something that doesn't cost $300!
Yes, KhanAcademy is one of the best. ;D But, really, the "variable soup" might be unintuitive, but it started out as such for all people. You just need to practice, practice, practice.
listen, i know people that come on here to mooch off y'all's goodwill
Answer: f(x) = 1 and g(x) = xx BUT Answer: no, f(x) = 1 and g(x) = xx are not the same function. The first function maps all values of x to 1. In essence, no matter what x is, the value f(x) will always equal 1. g(x) maps all values of x to the square of the number entered. For example, g(2) = 4 while f(2) = 1. Because the two functions do not have equivalent outputs for the same input, they cannot be the same function
reading math books is an art. they take practice and even then. so you have a 2tan(7x). or 2(f(g(x)) = 2 f '(g(x)) (g'(x)). so do you know what the derivative of tan(x) is? that will give you the f'(g(x)) where g(x) is the 7x function inside of the tangent. After you find that you will need the derivative of 7x which will be your g'(x) combine those to get 2(tan(7x))' (7x)'
SO DID THAT HELP???
but i promise i'm not that girl. i'm genuinely confused and pretty screwed... i really appreiate all of you
@hicksonm, I probably only speak for myself when I say this, but I don't come here to help people in the traditional sense. When someone asks a question, I answer it, not because I'm interested in them understanding it, but because I'm reinforcing MY understanding of it. So, when you post a question, it would be lovely for others like me if you asked about an understanding issue instead of just copy-pasting homework.
i come on here sometimes to help but yeah i do it alot for my own practice and (here's the nerd part) its fun haha
makes sense. i'm still too rusty to ask an intelligent question, but i will give it my best shot
There's no such thing as an "intelligent" question. There's only what you know, what you don't know, and the questions you have to ask to bridge the gap.
mostly, just seeing you all run through the steps with the problems has helped me to put some of the puzzle pieces together
but back to your problem. (tan(x))' = sec^2(x) (7x)' = 7 so 2(sec^2(7x))(7) = 14sec^2(7x)
yes...
just giving the answer to check your work with
thanks! i was answering yes to the "back to your problem" comment
so, when there is a constant separated out, you save it until the end?
like the 2?
you don't take the deravitive of the 2?
Answer: no, f(x) = 1 and g(x) = xx are not the same function. The first function maps all values of x to 1. In essence, no matter what x is, the value f(x) will always equal 1. g(x) maps all values of x to the square of the number entered. For example, g(2) = 4 while f(2) = 1. Because the two functions do not have equivalent outputs for the same input, they cannot be the same function SO IT IS........... f(x) = 1 and g(x) = xx
so, it's not defined? g'(x) doesn't =14sec^2(7x)?
let me check my work :/
i thought g was related to f in such a way that they weren't supposed to be equivalent? did i miss somehting big?
first off, you can always take the multiple in front of the derivative. a simple example. (7x)' = 7 if you take the 7 out and just do x, its 1*7 = 7 a little bigger problem= 3x^2. take the 3 out so take derivative of x^2 = 2x taking the 3 back in is 3*2x
I'm not sure how relevant this is for me to inject, but if you're finding math counterintuitive, and you can't get around that, it's probably because you see math like a jigsaw puzzle or Rubik's cube. Math is a language, a very *concise* and *logical* language. It's not a puzzle. Math is used to state and express puzzles and problems in a logical way, but math itself is a language. Never forget that.
what about the other person who said the functions were not equivalent?
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