Interesting limit: \[ \large \lim \limits_{x\to \infty} \frac{e^{px}}{x^{100}} \]
it's 0! lol
Nopes.
Assume p as +ve ;-)
this is inf/inf...let's do LH >:)) e^px(p)/100x^99 still no good... p^2e^px/9900x^98 still no good... this is the circle i have always hated >.<
Igb I choose this example to show you how to take care of things when L'Hop circles ;)
You're not in a circle. Just do it 100 times
i cannot find any manipulation here @_@ this is really good
Apply l'Hopital 100 times and you have \[ \frac{p^100}{100!} e^{px} \]
\[ \frac{p^{100}}{100!}e^{px} \]
but there is a smarter way ...
show us oh fool
lol, think for sometime Igb :)
Just tell us.
i have thought and i have shared my thoughts.
now it is time you taught us what you have thought
\[ \large \lim \limits_{x\to \infty} \frac{e^{px}}{x^{100}} = \left( \lim \limits_{x\to \infty} \frac{e^{\frac{px}{100}}}{x} \right)^{100} \] Now apply L'Hop ...
and you will get your answer \( \infty \)
just to get involved is p parameter in R?
I'd like a refund on this one.
if p>0 than the limit is infinity and if <0 it's zero
ffm do you know thayler's formula?
No, not even google http://www.google.co.in/search?q=thayler%27s+formula&nfpr=1&ie=UTF-8&sourceid=chrome&btnG=Search
or do you mean taylor's formula?
lol yeah that one... you can use it
Yes I know, but I think the way I showed above is easier ...
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