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Mathematics 45 Online
OpenStudy (anonymous):

According to The Fundamental Theorem of Algebra, how many zeros does the function f(x) = 24x5 + 8x3 - 2x - 15 have?

OpenStudy (anonymous):

USE DISCRIMANT

OpenStudy (anonymous):

You need to check the highest power of the X, then how many factors like (x-a), (x-b) are required to raise x to that power.

OpenStudy (jamesj):

@Juanita, No, that's wrong. The Fundamental Theorem of Algebra says that a polynomial of order n has n roots. Hence to apply the FTA to this problem, you need to know the order of this polynomial.

OpenStudy (jamesj):

The order of a polynomial, as mainaknag says, is the highest order of the variable.

OpenStudy (anonymous):

yes correct there are n zeores, the roots can be real or imaginary

OpenStudy (jamesj):

So Skate, what's the highest power of x in this polynomial? \[ f(x) = 24x^5 + 8x^3 - 2x - 15 \]

OpenStudy (anonymous):

i have no idea sorry

OpenStudy (anonymous):

24?

OpenStudy (anonymous):

What is the highest power of x? 24 is coefficient

OpenStudy (anonymous):

POWEr are exponents. so highest powere is 5

OpenStudy (jamesj):

\( x \) is x to the power of 1. \( x^2 \) is x to the power of two. Hence a polynomial \[ p(x) = 5x \] is of order 1. A polynomial \[ q(x) = 3x^2 - 7 \] is of order 2.

OpenStudy (jamesj):

So can you see now what is the highest power of x in your polynomial? Juanita just told you the answer.

OpenStudy (anonymous):

yes

OpenStudy (jamesj):

The highest power of x in \[ f(x) = 24x^5 + 8x^3 - 2x - 15 \] is \( x^5 \). Hence the polynomial is of fifth order. Hence by the FTA, it has ____ roots?

OpenStudy (jamesj):

The Fundamental Theorem of Algebra says that a polynomial of order n has n roots.

OpenStudy (anonymous):

5?

OpenStudy (anonymous):

or 4

OpenStudy (jamesj):

x^5 is the highest power ==> polynomial is of order 5 ==> polynomial has 5 roots, by the Fundamental Theorem of Algebra.

OpenStudy (jamesj):

Make sense?

OpenStudy (anonymous):

yes thank you

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