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OpenStudy (anonymous):
How many liters of oxygen gas at STP are needed to react completely with 8.0 of magnesium?
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OpenStudy (anonymous):
2Mg + O2 ---> 2MgO Moles of Mg: 8/ 24 = 1/3 mol Volume of O2 needed: (1/6) * 22.4 = 3.73 L
OpenStudy (anonymous):
3.7 L
OpenStudy (anonymous):
Can you better explain how you got the volume of O2 needed?
OpenStudy (anonymous):
Based the ratio mole that Oxygen = 1/2 of Magnesium!
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