Question

w^4-2w^2-2=0

Answer 1

will my answers have the sqrt symbol in it?

Answer 2

If w^2 = x, then:

x^2 - 2x - 2 = 0
x^2-2x = 2
x^2-2x + 1 = 2 + 1
(x-1)^2 = 3
x-1 = + or - sqrt(3)
x = + or - sqrt(3) + 1
w^2 = + or - sqrt(3) + 1
w = + or - sqrt(+ or - sqrt(3) + 1)

Answer 3

\[\sqrt{1+\sqrt{3}},-\sqrt{1+\sqrt{3}}\]

Answer 4

Crazy solution, but that should be correct

Answer 5

ok thats what i came up with, it that some what right?

Answer 6

That is the correct solution symbolically.

Answer 7

substitution w^2=t with condition t greater than or equal to zero...you get t^2-2t-2=0 solve it for t: