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OpenStudy (anonymous):
f(x)=x^3=x^2 g(x)= x^3/2+5
Determine (F o G)(1)
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OpenStudy (anonymous):
f(x)= x^3 + x^2
OpenStudy (anonymous):
(F o G)
who is "o"?
OpenStudy (anonymous):
f(g(1))
OpenStudy (mertsj):
I am confused by f(x)=x^3=x^2 Is that what it is supposed to say?
hero (hero):
I think you posted f(x) incorrectly @jfry
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OpenStudy (anonymous):
i did, it f(x)= x^3 + x^2
OpenStudy (mertsj):
Now who lectured me about exactly what he is doing?????
hero (hero):
I hope you're not referring to me. I didn't lecture you about anything
OpenStudy (mertsj):
\[f(g(x))=(x ^{\frac{3}{2}}+5)^{3}+(x ^{\frac{3}{2}}+5)^{2}\]
OpenStudy (anonymous):
Thank you
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OpenStudy (mertsj):
However, if all you want is the f(g(1)), the simplest approach would be to find the g(1) and put that result into f
OpenStudy (mertsj):
g(1)=6
f(6)=216+36=252
OpenStudy (anonymous):
Im not sure im getting this
OpenStudy (mertsj):
The f(g(x)) means replace every x in the function f with the function g
OpenStudy (anonymous):
i got it now, i was having trouble with the x^3/2. i thought it would be 1/2, not 1.
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OpenStudy (mertsj):
Sometimes it helps to make a diagram of the function f prepared to receive the function g|dw:1329525975930:dw|
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