Question

simplify 1-(-1(1-sin^2thita)everything ova 1-sin^2thita

Answer 1

any idea Sir?

Answer 2

(cosA+sinA)^2 +1
OR
2(1-sinAcosA)

Answer 3

Then, 1-(-1(1-sin^2thita)everything ova 1-sin^2thita can be thought of as:

[1 - ( -1 ( 1- sin ² Θ ) )] /[ ( 1 - sin ² Θ)] =

[1 - ( -1 (cos²Θ) ] / cos²Θ =

(1 + cos²Θ) / cos²Θ =

1/cos²Θ + cos²Θ / cos²Θ =

sec ² Θ + 1

Answer 4

we have
\[ \frac{1-(-(1-\sin^2 \theta))}{1-\sin^2\theta}\]
we know that
\[1-\sin^2\theta=\cos^2\theta\]
so
we get
\[ \frac{1-(-\cos^2\theta)}{\cos^2\theta}\]
we have now
\[ \frac{1+\cos^2\theta}{\cos^2\theta}\]
we get
\[\sec^2 \theta +1\]