use implicit differentiation to find equation of tangent line to -1x^2+3xy+4y^3=-8 at the point (-4,2)

Question

nenadmatematika · Answer

$$-2x+3y+3xy \prime+12y^2y \prime=0$$ $$y \prime(3x+12y^2)=2x-3y$$ $$y \prime=(2x-3y)/(3x+12y^2)$$ if you plug in the given point (-4,2) you get:$$(-8-6)/(-12+48)=-14/36=-7/18$$

anonymous · Answer

i need it in the form of y=mx + b, i forgot to mention. how do i find b

bahrom7893 · Answer

did i not answer this before?

anonymous · Answer

bathrom no, i made a mistake with the numbers

nenadmatematika · Answer

well I think : y-2=-7/18(x+4) so y=-7/18x+4/9  ....I would like someone to check this just in case :D

anonymous · Answer

*bahrom

anonymous · Answer

nena thats right, thanks for the help

nenadmatematika · Answer

haha :D I didn't notice that you wrote ''bathroom'' above haha :D

anonymous · Answer

typo

nenadmatematika · Answer

it's OK...you made me laugh so good :D  bahrom is nice dude he won't be mad :D

anonymous · Answer

yeah, he helped me out with this question earlier, but I accidentally gave him a couple different numbers which I just realized so his solution wasn't correct.

bahrom7893 · Answer

no for the numbers you gave me, my solution was correct :P

anonymous · Answer

yeah. true.

anonymous · Answer

thats all the help i needed thanks to both