Question

Write the equation of the line that passes through (1, 3) and (4, 4) in standard form

Answer 1

\[-x+3 y-8 = 0\]

Answer 2

1x - 3y = -8

Answer 3

-x+3y-8=0 is what i got

Answer 4

Standard Form: the standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers.

http://jwilson.coe.uga.edu/emt668/emat6680.2002/jackson/chapter%205%20lesson%20plan/day6.html

Answer 5

m = 1/3
4 = (1/3)4 + b
->b = 4 - 4/3 = 8/3
Thus y = x/3 + 8/3
3y = x + 8
x - 3y = 8

Answer 6

can some one do this one Write the equation of the line that passes through (2, 5) with a slope of 3 in point-slope form

Answer 7

So, I should write:

1x + (-3) y = -8

Answer 8

y -5 = 3 ( x -2)
y = 3x -1

Answer 9

yahooyc, did you see my reply?

Answer 10

i did but i dont have that option in my awser key

this is what i got
y – 2 = 3(x – 5)

y + 8 = 3(x + 5)

y + 5 = 3(x + 2)

y – 5 = 3(x – 2)

Answer 11

i dont know which one to pick

Answer 12

y – 5 = 3(x – 2)

Answer 13

The first step of my answer!

Answer 14

thank you everyone

Answer 15

The equation through 2 pts with slope is:
y - yA = m ( x - xA)

Answer 16

I need to fix my answer!
3y = x + 8
x - 3y = -8