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integrate (ln x)/x dx?
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What's the derivative of ln x?
And once you know that, does that suggest a substitution to you?
Actually I did get that far and then the internet went away: and I still got stuck I went with u=ln x which gives you du = 1/x dx and dx = x/1 du the x's cancel leaving \[\int\limits_{}^{}u du = \int\limits_{}^{}\ln x \] but apparently I'm blocking the integral for lnx or I've done something wrong...
After substitution of u = ln x, you have \[ \int u \ du = \frac{1}{2}u^2 + C = \frac{1}{2} (\ln x)^2 + C \]
thanks...is it weird that none of my books has \[\int\limits_{}^{}\ln x\] in the list of integral tables?
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