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7log9(x+8)=7
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Is 9 the base?
yeah
Divide both sides by 7
\[\log_{9}(x+8)=1 \]
Now put it into its exponential form.
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\[9^1=x+8\]
\[x=1\]
another way to solve it is by power rule.. log_9 (x+8)^7 = 7 change to exponential form 9^7 = (x+8)^7 get the seventh root of both sides 9 = x+8 x = 9-8 x=1 whichever you find more comfortable :D
7log9(x+8)=7 -> log9(x+8)=7/7 =1 => (x + 8) = 9 Thus x = 9 -8 = 1
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