Question

determine the value of 'x' that makes each sequence arithmetic.
d) x-4, 6, x
e) x+8, 2x+8, -x

Answer 1

if each term in the sequence is equidistant from the next we can write the difference between each term mathematically and set them equal\[6-(x-4)=x-6\]solve for x

Answer 2

...because each term is equidistant from the next in an arithmetic progression

Answer 3

so then
6-x+4=x-6
10-x=x-6
10+6=x+x
16=2x
8=x

yay ! thanks :)

Answer 4

welcome :D
same deal for the next one as well

Answer 5

so it would be 2x+8 - (x+8) = -x
right ?

Answer 6

you forgot the difference of the last terms
2x+8 - (x+8) = -x - (2x +8)

Answer 7

nvm,i got it,thanks man! its -2

Answer 8

call the entries of the series\[E_1,E_2,E_3\]if it is an arithmetic progression we have\[E_2-E_1=E_3-E_2\]is the idea...
again, welcome!