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Physics 22 Online
OpenStudy (anonymous):

A block of ice slides up a frictionless incline, starting at 0.500 . It stops, momentarily, 1.6 later. Find the inclination angle.

OpenStudy (anonymous):

Is the 1.6 a unit of time or distance?

OpenStudy (anonymous):

my bad, it is time. 1.6 seconds

OpenStudy (anonymous):

0.500 I take it is in ms^-2? Alright, so let's start with the component of gravitational acceleration parallel with the angle. gsin(n)=a, where g is the acceleration of gravity, n is the angle we're concerned with, and a is the aforementioned acceleration. We know that initial velocity, i, is i=0.5. Thus, we can write v=i+gsin(n)t, and solve for when v is 0. Questions?

OpenStudy (anonymous):

another mistake: 0.500 is actually m/s. so, can we be able to approach this problem with gsin(n)=a?

OpenStudy (anonymous):

Oh, yeah, that was MY mistake, haha. 0.500 is m/s, and it should work for the solution I provided. Do you understand it, though?

OpenStudy (anonymous):

i have to read it a couple of times, but yes i do understand the formula. thank you.

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