What is the Total Energy of an object that has mass of 6.98 kg, with a velocity of 1.92 m/s, which is also experiencing an acceleration of 9.94 m/s2 at a height of 9.43 m?

Question

anonymous · Answer

((1/2)mv^2)+mah=E

We're given m, v, a, AND h--that's literally every variable with which we can solve for E.

anonymous · Answer

That's what I thought, the problem is that the problem icludes an acceleration component: 9.94 m/s^2.  That means that:

E=KE + PE
KE = 1/2m * v^2
PE = mgh

So it would seem pretty simple:
KE = 1/2 * m * v^2
KE = 1/2 * 6.98kg * (1.92) ^2
KE = 12.86 J  (Joules)

PE = mgh
PE = 6.98 * 9.81 * 9.43
PE = 645.7 J

Therefore, 
E = PE + KE
E = 645.7 J + 12.86 J
E = 658.57 J

But that answer is WRONG.....  it's that extra A = 9.94 m/s^2 that is throwing me off somewhere...

anonymous · Answer

I also replaced the 9.81 (g) value with the 9.94 (A) value but the new answer (667.12 J) is still wrong.

anonymous · Answer

Interesting. Energy is a scalar, so I don't see there being any vector issues. Give me some time to brood over my mistake. XD

anonymous · Answer

thanks!