s(t)= 3t^2+2t-2
a. find the velocity for time t
b.find the acceleration for time t
c. compute the total distance
I derived the velocity equation and the acceleration as 5t+2 and 5 but the solution checker online says its wrong....
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OpenStudy (anonymous):
for c the interval is [0,1]
myininaya (myininaya):
v=s'=3(2)t+2=6t+2
OpenStudy (anonymous):
a. first derivative
b. 2nd derivative
c. s(1)
myininaya (myininaya):
your number in front of t is a little off
OpenStudy (anonymous):
wow.... this is what studying physics for 30 hours does to you....
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OpenStudy (anonymous):
how did i not see that rofl
OpenStudy (anonymous):
you guys probably are facepalming right now. "how is this kid in calc 1??"
OpenStudy (anonymous):
Hey can you do part c I think Im making another alegbra error and I cant see it I'm just not sure what to do with v=0 @ t=-1/3
OpenStudy (anonymous):
s(1)-s(0)???????
OpenStudy (anonymous):
as a thought jesus man you need more question marks?
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OpenStudy (anonymous):
Im pretty sure you can read more than just numbers as I said above I have been studying physics for 30 hours.
OpenStudy (anonymous):
maybe take a break!
OpenStudy (anonymous):
breaks are for sane people
OpenStudy (anonymous):
s(t)= 3t^2+2t-2
v = s'(t) = 6t^2 + 2
a = v'(t) = 12t