(3p^3)^2 X 4p^7 divided by 2(p^4)^3 =
18p ?
thanks I got 18p^8 ??
Is this the question:
@Vengeance --> Should your numerator be 36 p ^13 and then the denominator as is. I keep getting 18 p.
sounds good to me thanks. New to this and still learning
@Directrix-Yeah..7+6=13 omg epic fail..yeah its 18p
@njc27 ---> Do you want us to work out the steps of the problem here? Just say the word.
@directrix that would be great because now i am confused would you add the 7 & 6 and not multiply the sum is (3p^3)^2*4p^7/2(p^4)^3
I'll draw out the solution. First, a word. On a power of a power problem such as (x ^ 2 )^ 3, the exponents are multiplied to yield x^6 as the answer. This is because (x ^ 2) ^3 means the product of three x^2 terms or x^2 * x^2 * x^2 = x ^ (2+2+2) = x^6 power.
\[(3p ^{3})^{2}*4p ^{7}/2(p ^{4})^{3}\] \[9p ^{2*3}*4p ^{7}/2p ^{4*3}\] \[9p ^{6}*4p ^{7}/2p ^{12}\] \[36p ^{6+7}/2p ^{12}\] \[36p ^{13}/2p ^{12}\] \[18p ^{13-12}\] \[18p ^{1}\] \[18p\] If anything is wrong now please kill me.
Rules of exponents:\[a ^{m}*a ^{n}=a ^{m+n}\] \[(a ^{m})^{n}=a ^{m*n}=a ^{mn}\] \[a ^{m}/a ^{n}=a ^{m-n}\]
x^2 * x^3 is not a power of a power problem. The exponents are added because x^2 * x^3 means x*x* x*x*x = the product of five x terms or x^5. Note that x can be understood as x^1.
@ Vengeance --> It's fine.
Thank you very much that make a lot more sense now you are both wonderful. I'll try the next ones on my own. Just needed to be shown.
After you do one, post the question and the answer and we will check, if you like.
Thanks Directrix, and good idea. We can double check the answers.
Join our real-time social learning platform and learn together with your friends!