Integrate (2z)/(5z-1)
plz urgent help
um... long division?
its very complex by long divsionn,
use this. http://www.wolframalpha.com/bing/?i=integral+of+(2z)%2f(5z-1)&expl=3 all answers.
Use can put \(u=5z-1\), this is one way.
Mr m wrong
\[\frac{2z}{5z-1}=\frac25+\frac25\frac1{5z-1}\]
turing test cant understand the form plz write it clearly
? long division\[\int \frac{2z}{5z-1}=\int \frac25+\frac25\frac1{5z-1}dz\]\]
I don't really know how to illustrate the process on this site...
Mr math's sub works too
No, it's not wrong. Have you even tried it?
you can factor the 2 in the numerator out and it will be a bit simpler: \[\int \frac{2z}{5z-1} dz= 2\int \frac{z}{5z-1}dz=2\int\frac15+\frac1{5(5z-1)}dz\] Then split the integrals and go from there.
thanks
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