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OpenStudy (anonymous):
A moving car has kinetic energy. If it speeds up until it is going 4 times as fast, how much kinetic energy does it have in comparison?
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OpenStudy (jamesj):
Kinetic energy is proportional to speed squared, because \[ KE = \frac{1}{2}mv^2 \] So suppose you are initially traveling at a speed \( v_0 \). Then you travel 4 times faster, at a speed \( 4v_0 \). What is the ratio of the KE in those two cases?
OpenStudy (anonymous):
KE=8mV²
OpenStudy (jamesj):
Yes and how much more than the original KE is that?
OpenStudy (anonymous):
16 more than the original
OpenStudy (jamesj):
yes
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