Compute the following Bernoulli Trials:
1.) 3 successes in 5 trials with p = 2/7?
2.) 0 successes in 4 trials with p = 1/6?

Question

Compute the following Bernoulli Trials:
1.) 3 successes in 5 trials with p = 2/7?
2.) 0 successes in 4 trials with p = 1/6?

anonymous · Answer

do you know the formula for this?

anonymous · Answer

n = 5, k = 3, p = 2/7, 1-p= 5/7

anonymous · Answer

yes but I cant get it to work for some reason
I have tried numerous times and cant get the correct solution

anonymous · Answer

$$P(k=3)=\dbinom{5}{3}(\frac{2}{7})^3\times( \frac{5}{7})^2$$

anonymous · Answer

three sucesses explains the 
$$(\frac{2}{7})^3$$ 
2 failure explain 
$$(\frac{5}{7})^2$$ and there are 
$$\dbinom{5}{3}=10$$ ways to arrange the successes and failures

anonymous · Answer

here is what i got http://www.wolframalpha.com/input/?i=10%282%2F7%29^3*%285%2F7%29^2

anonymous · Answer

second one is easier, all failures is 
$$(\frac{5}{6})^4$$

anonymous · Answer

you got this ok?

anonymous · Answer

I think so it is a little clearer
thank you so much for your help

anonymous · Answer

yw