Question

Solve this system of equations.

x+y+z=-1
2x+5y+2z=1
-x+6y-3z=0

Answer 1

1 1 1 | -1
2 5 2 | 1
-1 6 -3 | 0
=
1 1 1 | -1 here i multiplied row 1 by -2 and added to row 2
0 3 0 | 3
-1 6 -3 | 0
=
1 1 1 | -1 here i added row 1 to row 3
0 3 0 | 3
0 7 -2 | -1

Answer 2

=
1 1 1 |-1
0 1 0 | 1 divided row 2 by 3
0 7 -2 | -1
=
1 1 1 | -1
0 1 0 | 1 here multiplied row 2 by -7 and added to row 3
0 0 -2| -8

Answer 3

1 1 1 | -1
0 1 0| 1
0 0 1| 4 divided row 3 by -2
=
1 0 1|-2
0 1 0| 1 here multiplied row 2 by -1 and added to row 1
0 0 1|4

Answer 4

=
1 0 0|-6
0 1 0| 1 here mutlpied row 3 by -1 and added to row 1
0 0 1|4

Answer 5

first column is the x column
second column is the y column
third column is the z column

Answer 6

so you have x=-6, y=1 ,z=4

Answer 7

you should check my arithmetic though

Answer 8

ok. thank you!