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OpenStudy (anonymous):
Does anybody know please how to calculate the percent water of KAl(SO4)2•12 H2O?
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OpenStudy (jfraser):
the formula of the hydrate tells us that 1 unit of alum (the salt) will be surrounded by 12 water molecules. This ratio is constant, so a MOLE of alum will have 12 MOLES of water surrounding it. The molar masses of these pieces are easy to find. The % water is calculated by:\[\%H{_2}O = \frac{MM (H{_2}O)}{MM(hydrate)} * 100\%\] I get about 54.4% water
OpenStudy (anonymous):
Thank you so much JFraser.
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