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Using differentiation from first principle rule prove how to find the derivative of f(x)=u(x)-v(x), when v'(x) and u'(x) are known
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f'(x)=u'(x)-v'(x)...
yahh i know that.. haha but how do you prove this??
Alright, let y=u+v, then y+dy=(u+du)+(v+dv) for infinitesimal distances; since dy=du+dv, as y=u+v can be taken out from the equation, dividing by dx will result in dy/dx=du/dx+dv/dx, and voila!
Using differentiation from first principle rule I think they want you to use \[\frac{df}{dx}= \lim_{\Delta x \rightarrow 0}\frac{f(x+ \Delta x)-f(x)}{\Delta x}\]
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